26-q2=100+q+3q2

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Solution for 26-q2=100+q+3q2 equation: 



26-q2=100+q+3q^2

We move all terms to the left:

26-q2-(100+q+3q^2)=0

We add all the numbers together, and all the variables

-1q^2-(100+q+3q^2)+26=0

We get rid of parentheses

-1q^2-3q^2-q-100+26=0

We add all the numbers together, and all the variables

-4q^2-1q-74=0

a = -4; b = -1; c = -74;
Δ = b2-4ac
Δ = -12-4·(-4)·(-74)
Δ = -1183
Delta is less than zero, so there is no solution for the equation

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