26-z=12+z

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Solution for 26-z=12+z equation: 



26-z=12+z

We move all terms to the left:

26-z-(12+z)=0

We add all the numbers together, and all the variables

-z-(z+12)+26=0

We add all the numbers together, and all the variables

-1z-(z+12)+26=0

We get rid of parentheses

-1z-z-12+26=0

We add all the numbers together, and all the variables

-2z+14=0

We move all terms containing z to the left, all other terms to the right

-2z=-14

z=-14/-2

z=+7

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