2625=0.042v2

Solution for 2625=0.042v2 equation:

2625=0.042v^2

We move all terms to the left:

2625-(0.042v^2)=0

We get rid of parentheses

-0.042v^2+2625=0

a = -0.042; b = 0; c = +2625;
Δ = b2-4ac
Δ = 02-4·(-0.042)·2625
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-21}{2*-0.042}=\frac{-21}{-0.084}
=249+0.084/0.084
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+21}{2*-0.042}=\frac{21}{-0.084}
=-249+0.084/0.084
$