2632=(2632-32y)/40+(32y)

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Solution for 2632=(2632-32y)/40+(32y) equation: 



2632=(2632-32y)/40+(32y)

We move all terms to the left:

2632-((2632-32y)/40+(32y))=0



Domain of the equation: 40+32y)!=0

We move all terms containing y to the left, all other terms to the right

32y)!=-40

y!=-40/1

y!=-40

y∈R



We add all the numbers together, and all the variables

-((-32y+2632)/40+32y)+2632=0

We multiply all the terms by the denominator


-((-32y+2632)+2632*40+32y)=0



We calculate terms in parentheses: -((-32y+2632)+2632*40+32y), so:

(-32y+2632)+2632*40+32y

determiningTheFunctionDomain
(-32y+2632)+32y+2632*40

We add all the numbers together, and all the variables

32y+(-32y+2632)+105280

We get rid of parentheses

32y-32y+2632+105280

We add all the numbers together, and all the variables

107912

Back to the equation:

-(107912)



We move all terms containing y to the left, all other terms to the right

=107912

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