26=(2x-6)(x-3)

Solution for 26=(2x-6)(x-3) equation:

26=(2x-6)(x-3)

We move all terms to the left:

26-((2x-6)(x-3))=0

We multiply parentheses ..

-((+2x^2-6x-6x+18))+26=0


We calculate terms in parentheses: -((+2x^2-6x-6x+18)), so:

(+2x^2-6x-6x+18)

We get rid of parentheses

2x^2-6x-6x+18

We add all the numbers together, and all the variables

2x^2-12x+18

Back to the equation:

-(2x^2-12x+18)


We get rid of parentheses

-2x^2+12x-18+26=0

We add all the numbers together, and all the variables

-2x^2+12x+8=0

a = -2; b = 12; c = +8;
Δ = b2-4ac
Δ = 122-4·(-2)·8
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{13}}{2*-2}=\frac{-12-4\sqrt{13}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{13}}{2*-2}=\frac{-12+4\sqrt{13}}{-4}
$