26=2(b-1)+8(5b-7)

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Solution for 26=2(b-1)+8(5b-7) equation: 



26=2(b-1)+8(5b-7)

We move all terms to the left:

26-(2(b-1)+8(5b-7))=0



We calculate terms in parentheses: -(2(b-1)+8(5b-7)), so:

2(b-1)+8(5b-7)

We multiply parentheses

2b+40b-2-56

We add all the numbers together, and all the variables

42b-58

Back to the equation:

-(42b-58)



We get rid of parentheses

-42b+58+26=0

We add all the numbers together, and all the variables

-42b+84=0

We move all terms containing b to the left, all other terms to the right

-42b=-84

b=-84/-42

b=+2

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