26=20+3/4z

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Solution for 26=20+3/4z equation: 



26=20+3/4z

We move all terms to the left:

26-(20+3/4z)=0



Domain of the equation: 4z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-(3/4z+20)+26=0

We get rid of parentheses

-3/4z-20+26=0

We multiply all the terms by the denominator


-20*4z+26*4z-3=0

Wy multiply elements

-80z+104z-3=0

We add all the numbers together, and all the variables

24z-3=0

We move all terms containing z to the left, all other terms to the right

24z=3

z=3/24

z=1/8

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