26=b+(3b-2)

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Solution for 26=b+(3b-2) equation: 



26=b+(3b-2)

We move all terms to the left:

26-(b+(3b-2))=0



We calculate terms in parentheses: -(b+(3b-2)), so:

b+(3b-2)

We get rid of parentheses

b+3b-2

We add all the numbers together, and all the variables

4b-2

Back to the equation:

-(4b-2)



We get rid of parentheses

-4b+2+26=0

We add all the numbers together, and all the variables

-4b+28=0

We move all terms containing b to the left, all other terms to the right

-4b=-28

b=-28/-4

b=+7

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