26=v2

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Solution for 26=v2 equation:



26=v2
We move all terms to the left:
26-(v2)=0
We add all the numbers together, and all the variables
-1v^2+26=0
a = -1; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-1)·26
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{26}}{2*-1}=\frac{0-2\sqrt{26}}{-2} =-\frac{2\sqrt{26}}{-2} =-\frac{\sqrt{26}}{-1} $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{26}}{2*-1}=\frac{0+2\sqrt{26}}{-2} =\frac{2\sqrt{26}}{-2} =\frac{\sqrt{26}}{-1} $

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