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26x^2+104x=0
a = 26; b = 104; c = 0;
Δ = b2-4ac
Δ = 1042-4·26·0
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10816}=104$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-104}{2*26}=\frac{-208}{52} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+104}{2*26}=\frac{0}{52} =0 $
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