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26x^2+18x=48x=6
We move all terms to the left:
26x^2+18x-(48x)=0
We add all the numbers together, and all the variables
26x^2-30x=0
a = 26; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·26·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*26}=\frac{0}{52} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*26}=\frac{60}{52} =1+2/13 $
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