27(10+x)=-3(20+x)

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Solution for 27(10+x)=-3(20+x) equation: 



27(10+x)=-3(20+x)

We move all terms to the left:

27(10+x)-(-3(20+x))=0

We add all the numbers together, and all the variables

27(x+10)-(-3(x+20))=0

We multiply parentheses

27x-(-3(x+20))+270=0



We calculate terms in parentheses: -(-3(x+20)), so:

-3(x+20)

We multiply parentheses

-3x-60

Back to the equation:

-(-3x-60)



We get rid of parentheses

27x+3x+60+270=0

We add all the numbers together, and all the variables

30x+330=0

We move all terms containing x to the left, all other terms to the right

30x=-330

x=-330/30

x=-11

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