27(2b-1/3)

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Solution for 27(2b-1/3) equation: 


b in (-oo:+oo)

27*(2*b-(1/3)) = 0

27*(2*b-1/3) = 0

( 2*b-1/3 )

2*b-1/3 = 0 // + 1/3

2*b = 1/3 // : 2

b = 1/3/2

b = 1/6

( 27 )

27 = 0

b belongs to the empty set

b = 1/6

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