27+2x=3(-x+4)-20

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Solution for 27+2x=3(-x+4)-20 equation: 



27+2x=3(-x+4)-20

We move all terms to the left:

27+2x-(3(-x+4)-20)=0

We add all the numbers together, and all the variables

2x-(3(-1x+4)-20)+27=0



We calculate terms in parentheses: -(3(-1x+4)-20), so:

3(-1x+4)-20

We multiply parentheses

-3x+12-20

We add all the numbers together, and all the variables

-3x-8

Back to the equation:

-(-3x-8)



We get rid of parentheses

2x+3x+8+27=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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