27+3y-11=13y-12-3y

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Solution for 27+3y-11=13y-12-3y equation: 



27+3y-11=13y-12-3y

We move all terms to the left:

27+3y-11-(13y-12-3y)=0

We add all the numbers together, and all the variables

3y-(10y-12)+27-11=0

We add all the numbers together, and all the variables

3y-(10y-12)+16=0

We get rid of parentheses

3y-10y+12+16=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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