27+3y-7=12y-10-4y

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Solution for 27+3y-7=12y-10-4y equation: 



27+3y-7=12y-10-4y

We move all terms to the left:

27+3y-7-(12y-10-4y)=0

We add all the numbers together, and all the variables

3y-(8y-10)+27-7=0

We add all the numbers together, and all the variables

3y-(8y-10)+20=0

We get rid of parentheses

3y-8y+10+20=0

We add all the numbers together, and all the variables

-5y+30=0

We move all terms containing y to the left, all other terms to the right

-5y=-30

y=-30/-5

y=+6

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