27+3y=9y+12

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Solution for 27+3y=9y+12 equation: 



27+3y=9y+12

We move all terms to the left:

27+3y-(9y+12)=0

We get rid of parentheses

3y-9y-12+27=0

We add all the numbers together, and all the variables

-6y+15=0

We move all terms containing y to the left, all other terms to the right

-6y=-15

y=-15/-6

y=2+1/2

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