27-(2c+4)=2(c+4)+6

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Solution for 27-(2c+4)=2(c+4)+6 equation:



27-(2c+4)=2(c+4)+6
We move all terms to the left:
27-(2c+4)-(2(c+4)+6)=0
We get rid of parentheses
-2c-(2(c+4)+6)-4+27=0
We calculate terms in parentheses: -(2(c+4)+6), so:
2(c+4)+6
We multiply parentheses
2c+8+6
We add all the numbers together, and all the variables
2c+14
Back to the equation:
-(2c+14)
We add all the numbers together, and all the variables
-2c-(2c+14)+23=0
We get rid of parentheses
-2c-2c-14+23=0
We add all the numbers together, and all the variables
-4c+9=0
We move all terms containing c to the left, all other terms to the right
-4c=-9
c=-9/-4
c=2+1/4

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