27-(5b-4b)=(7b-1)+(3b+6)

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Solution for 27-(5b-4b)=(7b-1)+(3b+6) equation: 



27-(5b-4b)=(7b-1)+(3b+6)

We move all terms to the left:

27-(5b-4b)-((7b-1)+(3b+6))=0

We add all the numbers together, and all the variables

-(+b)-((7b-1)+(3b+6))+27=0

We get rid of parentheses

-b-((7b-1)+(3b+6))+27=0



We calculate terms in parentheses: -((7b-1)+(3b+6)), so:

(7b-1)+(3b+6)

We get rid of parentheses

7b+3b-1+6

We add all the numbers together, and all the variables

10b+5

Back to the equation:

-(10b+5)



We add all the numbers together, and all the variables

-1b-(10b+5)+27=0

We get rid of parentheses

-1b-10b-5+27=0

We add all the numbers together, and all the variables

-11b+22=0

We move all terms containing b to the left, all other terms to the right

-11b=-22

b=-22/-11

b=+2

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