27-10(4n+3)=6(6n+2)-56n

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Solution for 27-10(4n+3)=6(6n+2)-56n equation: 



27-10(4n+3)=6(6n+2)-56n

We move all terms to the left:

27-10(4n+3)-(6(6n+2)-56n)=0

We multiply parentheses

-40n-(6(6n+2)-56n)-30+27=0



We calculate terms in parentheses: -(6(6n+2)-56n), so:

6(6n+2)-56n

We add all the numbers together, and all the variables

-56n+6(6n+2)

We multiply parentheses

-56n+36n+12

We add all the numbers together, and all the variables

-20n+12

Back to the equation:

-(-20n+12)



We add all the numbers together, and all the variables

-40n-(-20n+12)-3=0

We get rid of parentheses

-40n+20n-12-3=0

We add all the numbers together, and all the variables

-20n-15=0

We move all terms containing n to the left, all other terms to the right

-20n=15

n=15/-20

n=-3/4

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