27-3+8y-4(y+4)=-4(5y-3)-7(y-1)-14y+6

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Solution for 27-3+8y-4(y+4)=-4(5y-3)-7(y-1)-14y+6 equation: 



27-3+8y-4(y+4)=-4(5y-3)-7(y-1)-14y+6

We move all terms to the left:

27-3+8y-4(y+4)-(-4(5y-3)-7(y-1)-14y+6)=0

We add all the numbers together, and all the variables

8y-4(y+4)-(-4(5y-3)-7(y-1)-14y+6)+24=0

We multiply parentheses

8y-4y-(-4(5y-3)-7(y-1)-14y+6)-16+24=0



We calculate terms in parentheses: -(-4(5y-3)-7(y-1)-14y+6), so:

-4(5y-3)-7(y-1)-14y+6

We add all the numbers together, and all the variables

-14y-4(5y-3)-7(y-1)+6

We multiply parentheses

-14y-20y-7y+12+7+6

We add all the numbers together, and all the variables

-41y+25

Back to the equation:

-(-41y+25)



We add all the numbers together, and all the variables

4y-(-41y+25)+8=0

We get rid of parentheses

4y+41y-25+8=0

We add all the numbers together, and all the variables

45y-17=0

We move all terms containing y to the left, all other terms to the right

45y=17

y=17/45

y=17/45

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