27-4(3c-6)+3c+6(-7+c)=10

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Solution for 27-4(3c-6)+3c+6(-7+c)=10 equation: 



27-4(3c-6)+3c+6(-7+c)=10

We move all terms to the left:

27-4(3c-6)+3c+6(-7+c)-(10)=0

We add all the numbers together, and all the variables

-4(3c-6)+3c+6(c-7)+27-10=0

We add all the numbers together, and all the variables

3c-4(3c-6)+6(c-7)+17=0

We multiply parentheses

3c-12c+6c+24-42+17=0

We add all the numbers together, and all the variables

-3c-1=0

We move all terms containing c to the left, all other terms to the right

-3c=1

c=1/-3

c=-1/3

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