27-4K=4K+3(k-2)

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Solution for 27-4K=4K+3(k-2) equation: 



27-4=4+3(K-2)

We move all terms to the left:

27-4-(4+3(K-2))=0

We add all the numbers together, and all the variables

-(4+3(K-2))+23=0



We calculate terms in parentheses: -(4+3(K-2)), so:

4+3(K-2)

determiningTheFunctionDomain
3(K-2)+4

We multiply parentheses

3K-6+4

We add all the numbers together, and all the variables

3K-2

Back to the equation:

-(3K-2)



We get rid of parentheses

-3K+2+23=0

We add all the numbers together, and all the variables

-3K+25=0

We move all terms containing K to the left, all other terms to the right

-3K=-25

K=-25/-3

K=8+1/3

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