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27-4x=-7x(1+3x)
We move all terms to the left:
27-4x-(-7x(1+3x))=0
We add all the numbers together, and all the variables
-4x-(-7x(3x+1))+27=0
We calculate terms in parentheses: -(-7x(3x+1)), so:We get rid of parentheses
-7x(3x+1)
We multiply parentheses
-21x^2-7x
Back to the equation:
-(-21x^2-7x)
21x^2+7x-4x+27=0
We add all the numbers together, and all the variables
21x^2+3x+27=0
a = 21; b = 3; c = +27;
Δ = b2-4ac
Δ = 32-4·21·27
Δ = -2259
Delta is less than zero, so there is no solution for the equation
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