27-6b=3(b+3)-3(3b-6)

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Solution for 27-6b=3(b+3)-3(3b-6) equation: 



27-6b=3(b+3)-3(3b-6)

We move all terms to the left:

27-6b-(3(b+3)-3(3b-6))=0



We calculate terms in parentheses: -(3(b+3)-3(3b-6)), so:

3(b+3)-3(3b-6)

We multiply parentheses

3b-9b+9+18

We add all the numbers together, and all the variables

-6b+27

Back to the equation:

-(-6b+27)



We get rid of parentheses

-6b+6b-27+27=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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