27/(3x)=(12x)/48

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Solution for 27/(3x)=(12x)/48 equation: 


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

27/(3*x) = (12*x)/48 // - (12*x)/48

27/(3*x)-((12*x)/48) = 0

(-1/4)*x+27/(3*x) = 0

9*x^-1-1/4*x^1 = 0

(9*x^0-1/4*x^2)/(x^1) = 0 // * x^2

x^1*(9*x^0-1/4*x^2) = 0

x^1

(-1/4)*x^2+9 = 0

(-1/4)*x^2+9 = 0

DELTA = 0^2-(4*9*(-1/4))

DELTA = 9

DELTA > 0

x = (9^(1/2)+0)/(2*(-1/4)) or x = (0-9^(1/2))/(2*(-1/4))

x = -6 or x = 6

x in { -6, 6} 

x in { -6, 6 }

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