27/3zx

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Solution for 27/3zx equation: 


1*x^3+1*x^2-(17*x)+15 = 0

Y = (3/2)*x-(3/2)

x^3*((3*((15*x^5)/y)*y)/5) = 0

k^5*((36*k^3*m^4)/30)*m = 0

4*x^5-3*x^3+2;x-3

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