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270=2x+4/3x
We move all terms to the left:
270-(2x+4/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2x+4/3x)+270=0
We get rid of parentheses
-2x-4/3x+270=0
We multiply all the terms by the denominator
-2x*3x+270*3x-4=0
Wy multiply elements
-6x^2+810x-4=0
a = -6; b = 810; c = -4;
Δ = b2-4ac
Δ = 8102-4·(-6)·(-4)
Δ = 656004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{656004}=\sqrt{4*164001}=\sqrt{4}*\sqrt{164001}=2\sqrt{164001}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(810)-2\sqrt{164001}}{2*-6}=\frac{-810-2\sqrt{164001}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(810)+2\sqrt{164001}}{2*-6}=\frac{-810+2\sqrt{164001}}{-12} $
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