27=(4+m)-5

Solution for 27=(4+m)-5 equation:

27=(4+m)-5

We move all terms to the left:

27-((4+m)-5)=0

We add all the numbers together, and all the variables

-((m+4)-5)+27=0


We calculate terms in parentheses: -((m+4)-5), so:

(m+4)-5

We get rid of parentheses

m+4-5

We add all the numbers together, and all the variables

m-1

Back to the equation:

-(m-1)


We get rid of parentheses

-m+1+27=0

We add all the numbers together, and all the variables

-1m+28=0

We move all terms containing m to the left, all other terms to the right

-m=-28

m=-28/-1

m=+28