27=-3(23-y)+3(y-4)

Solution for 27=-3(23-y)+3(y-4) equation:

27=-3(23-y)+3(y-4)

We move all terms to the left:

27-(-3(23-y)+3(y-4))=0

We add all the numbers together, and all the variables

-(-3(-1y+23)+3(y-4))+27=0


We calculate terms in parentheses: -(-3(-1y+23)+3(y-4)), so:

-3(-1y+23)+3(y-4)

We multiply parentheses

3y+3y-69-12

We add all the numbers together, and all the variables

6y-81

Back to the equation:

-(6y-81)


We get rid of parentheses

-6y+81+27=0

We add all the numbers together, and all the variables

-6y+108=0

We move all terms containing y to the left, all other terms to the right

-6y=-108

y=-108/-6

y=+18