27=-3(23-y)+3(y-4)

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Solution for 27=-3(23-y)+3(y-4) equation:



27=-3(23-y)+3(y-4)
We move all terms to the left:
27-(-3(23-y)+3(y-4))=0
We add all the numbers together, and all the variables
-(-3(-1y+23)+3(y-4))+27=0
We calculate terms in parentheses: -(-3(-1y+23)+3(y-4)), so:
-3(-1y+23)+3(y-4)
We multiply parentheses
3y+3y-69-12
We add all the numbers together, and all the variables
6y-81
Back to the equation:
-(6y-81)
We get rid of parentheses
-6y+81+27=0
We add all the numbers together, and all the variables
-6y+108=0
We move all terms containing y to the left, all other terms to the right
-6y=-108
y=-108/-6
y=+18

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