27=-6(n-5)-(3-n)

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Solution for 27=-6(n-5)-(3-n) equation: 



27=-6(n-5)-(3-n)

We move all terms to the left:

27-(-6(n-5)-(3-n))=0

We add all the numbers together, and all the variables

-(-6(n-5)-(-1n+3))+27=0



We calculate terms in parentheses: -(-6(n-5)-(-1n+3)), so:

-6(n-5)-(-1n+3)

We multiply parentheses

-6n-(-1n+3)+30

We get rid of parentheses

-6n+1n-3+30

We add all the numbers together, and all the variables

-5n+27

Back to the equation:

-(-5n+27)



We get rid of parentheses

5n-27+27=0

We add all the numbers together, and all the variables

5n=0

n=0/5

n=0

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