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27=-a(a+5)+6(a+8)
We move all terms to the left:
27-(-a(a+5)+6(a+8))=0
We calculate terms in parentheses: -(-a(a+5)+6(a+8)), so:We get rid of parentheses
-a(a+5)+6(a+8)
We multiply parentheses
-a^2-5a+6a+48
We add all the numbers together, and all the variables
-1a^2+a+48
Back to the equation:
-(-1a^2+a+48)
1a^2-a-48+27=0
We add all the numbers together, and all the variables
a^2-1a-21=0
a = 1; b = -1; c = -21;
Δ = b2-4ac
Δ = -12-4·1·(-21)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{85}}{2*1}=\frac{1-\sqrt{85}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{85}}{2*1}=\frac{1+\sqrt{85}}{2} $
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