27=16-(2z-2)

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Solution for 27=16-(2z-2) equation: 



27=16-(2z-2)

We move all terms to the left:

27-(16-(2z-2))=0



We calculate terms in parentheses: -(16-(2z-2)), so:

16-(2z-2)

determiningTheFunctionDomain
-(2z-2)+16

We get rid of parentheses

-2z+2+16

We add all the numbers together, and all the variables

-2z+18

Back to the equation:

-(-2z+18)



We get rid of parentheses

2z-18+27=0

We add all the numbers together, and all the variables

2z+9=0

We move all terms containing z to the left, all other terms to the right

2z=-9

z=-9/2

z=-4+1/2

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