27=2+7(z-4)

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Solution for 27=2+7(z-4) equation:



27=2+7(z-4)
We move all terms to the left:
27-(2+7(z-4))=0
We calculate terms in parentheses: -(2+7(z-4)), so:
2+7(z-4)
determiningTheFunctionDomain 7(z-4)+2
We multiply parentheses
7z-28+2
We add all the numbers together, and all the variables
7z-26
Back to the equation:
-(7z-26)
We get rid of parentheses
-7z+26+27=0
We add all the numbers together, and all the variables
-7z+53=0
We move all terms containing z to the left, all other terms to the right
-7z=-53
z=-53/-7
z=7+4/7

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