27=3+2(t+4)

Solution for 27=3+2(t+4) equation:

27=3+2(t+4)

We move all terms to the left:

27-(3+2(t+4))=0


We calculate terms in parentheses: -(3+2(t+4)), so:

3+2(t+4)

determiningTheFunctionDomain
2(t+4)+3

We multiply parentheses

2t+8+3

We add all the numbers together, and all the variables

2t+11

Back to the equation:

-(2t+11)


We get rid of parentheses

-2t-11+27=0

We add all the numbers together, and all the variables

-2t+16=0

We move all terms containing t to the left, all other terms to the right

-2t=-16

t=-16/-2

t=+8