27=3c-+(6c-2c)

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Solution for 27=3c-+(6c-2c) equation: 



27=3c-+(6c-2c)

We move all terms to the left:

27-(3c-+(6c-2c))=0

We add all the numbers together, and all the variables

-(3c-+(+4c))+27=0

We use the square of the difference formula

-(3c-(+4c))+27=0



We calculate terms in parentheses: -(3c-(+4c)), so:

3c-(+4c)

We get rid of parentheses

3c-4c

We add all the numbers together, and all the variables

-c

Back to the equation:

-(-c)



We add all the numbers together, and all the variables

-(-1c)+27=0

We get rid of parentheses

1c+27=0

We add all the numbers together, and all the variables

c+27=0

We move all terms containing c to the left, all other terms to the right

c=-27

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