27=3c-3(3-2c)

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Solution for 27=3c-3(3-2c) equation: 



27=3c-3(3-2c)

We move all terms to the left:

27-(3c-3(3-2c))=0

We add all the numbers together, and all the variables

-(3c-3(-2c+3))+27=0



We calculate terms in parentheses: -(3c-3(-2c+3)), so:

3c-3(-2c+3)

We multiply parentheses

3c+6c-9

We add all the numbers together, and all the variables

9c-9

Back to the equation:

-(9c-9)



We get rid of parentheses

-9c+9+27=0

We add all the numbers together, and all the variables

-9c+36=0

We move all terms containing c to the left, all other terms to the right

-9c=-36

c=-36/-9

c=+4

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