27=3c-3(6-26)

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Solution for 27=3c-3(6-26) equation: 



27=3c-3(6-26)

We move all terms to the left:

27-(3c-3(6-26))=0

We add all the numbers together, and all the variables

-(3c-3(-20))+27=0



We calculate terms in parentheses: -(3c-3(-20)), so:

3c-3(-20)

We add all the numbers together, and all the variables

3c+60

Back to the equation:

-(3c+60)



We get rid of parentheses

-3c-60+27=0

We add all the numbers together, and all the variables

-3c-33=0

We move all terms containing c to the left, all other terms to the right

-3c=33

c=33/-3

c=-11

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