27=3c-3(6-2c)-

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Solution for 27=3c-3(6-2c)- equation: 



27=3c-3(6-2c)-

We move all terms to the left:

27-(3c-3(6-2c)-)=0

We add all the numbers together, and all the variables

-(3c-3(-2c+6)-)+27=0



We calculate terms in parentheses: -(3c-3(-2c+6)-), so:

3c-3(-2c+6)-

We add all the numbers together, and all the variables

3c-3(-2c+6)

We multiply parentheses

3c+6c-18

We add all the numbers together, and all the variables

9c-18

Back to the equation:

-(9c-18)



We get rid of parentheses

-9c+18+27=0

We add all the numbers together, and all the variables

-9c+45=0

We move all terms containing c to the left, all other terms to the right

-9c=-45

c=-45/-9

c=+5

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