27=3c-3(6-2c)=

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Solution for 27=3c-3(6-2c)= equation:



27=3c-3(6-2c)=
We move all terms to the left:
27-(3c-3(6-2c))=0
We add all the numbers together, and all the variables
-(3c-3(-2c+6))+27=0
We calculate terms in parentheses: -(3c-3(-2c+6)), so:
3c-3(-2c+6)
We multiply parentheses
3c+6c-18
We add all the numbers together, and all the variables
9c-18
Back to the equation:
-(9c-18)
We get rid of parentheses
-9c+18+27=0
We add all the numbers together, and all the variables
-9c+45=0
We move all terms containing c to the left, all other terms to the right
-9c=-45
c=-45/-9
c=+5

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