27=3c-3(6-2c)=27

Solution for 27=3c-3(6-2c)=27 equation:

27=3c-3(6-2c)=27

We move all terms to the left:

27-(3c-3(6-2c))=0

We add all the numbers together, and all the variables

-(3c-3(-2c+6))+27=0


We calculate terms in parentheses: -(3c-3(-2c+6)), so:

3c-3(-2c+6)

We multiply parentheses

3c+6c-18

We add all the numbers together, and all the variables

9c-18

Back to the equation:

-(9c-18)


We get rid of parentheses

-9c+18+27=0

We add all the numbers together, and all the variables

-9c+45=0

We move all terms containing c to the left, all other terms to the right

-9c=-45

c=-45/-9

c=+5