27=6(8c-2)

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Solution for 27=6(8c-2) equation: 



27=6(8c-2)

We move all terms to the left:

27-(6(8c-2))=0



We calculate terms in parentheses: -(6(8c-2)), so:

6(8c-2)

We multiply parentheses

48c-12

Back to the equation:

-(48c-12)



We get rid of parentheses

-48c+12+27=0

We add all the numbers together, and all the variables

-48c+39=0

We move all terms containing c to the left, all other terms to the right

-48c=-39

c=-39/-48

c=13/16

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