27=7(x-4)+4(2x-3)

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Solution for 27=7(x-4)+4(2x-3) equation: 



27=7(x-4)+4(2x-3)

We move all terms to the left:

27-(7(x-4)+4(2x-3))=0



We calculate terms in parentheses: -(7(x-4)+4(2x-3)), so:

7(x-4)+4(2x-3)

We multiply parentheses

7x+8x-28-12

We add all the numbers together, and all the variables

15x-40

Back to the equation:

-(15x-40)



We get rid of parentheses

-15x+40+27=0

We add all the numbers together, and all the variables

-15x+67=0

We move all terms containing x to the left, all other terms to the right

-15x=-67

x=-67/-15

x=4+7/15

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