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27=7-3(2x+5)-x
We move all terms to the left:
27-(7-3(2x+5)-x)=0
We calculate terms in parentheses: -(7-3(2x+5)-x), so:We get rid of parentheses
7-3(2x+5)-x
determiningTheFunctionDomain -3(2x+5)-x+7
We add all the numbers together, and all the variables
-1x-3(2x+5)+7
We multiply parentheses
-1x-6x-15+7
We add all the numbers together, and all the variables
-7x-8
Back to the equation:
-(-7x-8)
7x+8+27=0
We add all the numbers together, and all the variables
7x+35=0
We move all terms containing x to the left, all other terms to the right
7x=-35
x=-35/7
x=-5
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