27=9/5c+32

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Solution for 27=9/5c+32 equation: 



27=9/5c+32

We move all terms to the left:

27-(9/5c+32)=0



Domain of the equation: 5c+32)!=0

c∈R



We get rid of parentheses

-9/5c-32+27=0

We multiply all the terms by the denominator


-32*5c+27*5c-9=0

Wy multiply elements

-160c+135c-9=0

We add all the numbers together, and all the variables

-25c-9=0

We move all terms containing c to the left, all other terms to the right

-25c=9

c=9/-25

c=-9/25

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