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27=9x^2
We move all terms to the left:
27-(9x^2)=0
a = -9; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-9)·27
Δ = 972
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{972}=\sqrt{324*3}=\sqrt{324}*\sqrt{3}=18\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{3}}{2*-9}=\frac{0-18\sqrt{3}}{-18} =-\frac{18\sqrt{3}}{-18} =-\frac{\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{3}}{2*-9}=\frac{0+18\sqrt{3}}{-18} =\frac{18\sqrt{3}}{-18} =\frac{\sqrt{3}}{-1} $
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