27=b/2*3b

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Solution for 27=b/2*3b equation: 


b in (-oo:+oo)

27 = 3*(b/2)*b // - 3*(b/2)*b

27-(3*(b/2)*b) = 0

(-3/2)*b^2+27 = 0

-3/2*b^2 = -27 // : -3/2

b^2 = 18

b^2 = 18 // ^ 1/2

abs(b) = 3*2^(1/2)

b = 3*2^(1/2) or b = -(3*2^(1/2))

b in { 3*2^(1/2), -(3*2^(1/2)) }

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