27=x(3-2x)

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Solution for 27=x(3-2x) equation: 



27=x(3-2x)

We move all terms to the left:

27-(x(3-2x))=0

We add all the numbers together, and all the variables

-(x(-2x+3))+27=0



We calculate terms in parentheses: -(x(-2x+3)), so:

x(-2x+3)

We multiply parentheses

-2x^2+3x

Back to the equation:

-(-2x^2+3x)



We get rid of parentheses

2x^2-3x+27=0

a = 2; b = -3; c = +27;
Δ = b2-4ac
Δ = -32-4·2·27
Δ = -207
Delta is less than zero, so there is no solution for the equation

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