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27h^2+6h-1=0
a = 27; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·27·(-1)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12}{2*27}=\frac{-18}{54} =-1/3 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12}{2*27}=\frac{6}{54} =1/9 $
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