27n-22n=24(n+9)+2(n-3)

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Solution for 27n-22n=24(n+9)+2(n-3) equation: 



27n-22n=24(n+9)+2(n-3)

We move all terms to the left:

27n-22n-(24(n+9)+2(n-3))=0

We add all the numbers together, and all the variables

5n-(24(n+9)+2(n-3))=0



We calculate terms in parentheses: -(24(n+9)+2(n-3)), so:

24(n+9)+2(n-3)

We multiply parentheses

24n+2n+216-6

We add all the numbers together, and all the variables

26n+210

Back to the equation:

-(26n+210)



We get rid of parentheses

5n-26n-210=0

We add all the numbers together, and all the variables

-21n-210=0

We move all terms containing n to the left, all other terms to the right

-21n=210

n=210/-21

n=-10

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